Question

a particle starts to move in a straight line from a point with a velocity of 10m/s and acceleration of 2.0 m/s^2 . Find the velocity of the position if it's
a) t = 5s
b) t = 10s​

Answer 1

Answer:

at t=5s the velocity of the block is 20m/s,at t=10s the velocity is 30m/s

Explanation:

acceleration 2m/s^2 means for one second the velocity increase with the factor 2.so for 5s it will increase by the factor 10and for 10s it will increase by the factor 20

Answer 2

U=10 m/ s

a=2 m/ s²

At t=5sec

$v = u + at \\ v = 10 + 2 \times 5 \\ v = 20 \frac{m}{s}$

At t=10sec

$v = 10 + 2 \times 10 \\ v = 30 \frac{m}{s}$

i hope this helps ( ╹▽╹ )