Physics, asked by Ahiri2004, 9 months ago

A particle starts with a velocity of 10 metre per second having a deceleration of 2 metre per second square find displacement and distance travelled in 30 seconds​

Answers

Answered by piyushogi
1

Answer:

Displacement = 600m

Explanation:

Given,

s = ? , t = 30s , u = 10 m/s , a = -2 m/s

s = ut + 1/2 x at²

  = 10*30 + 1/2* (-2)(30)²

  = 300 - 900

  = -600

∴ As displacement cannot be negative , it is 600m

Hope it helps..!!

Mark brainliest...!!

Answered by nagathegenius
1

Answer:

Explanation:

It comes to rest at t=5sec

Displacement in 5 sec = 25m

Displacement in 30 sec = -600m

Displacement in 5 to 30s = -625

Distance in 5 to 30 sec = 625m

Distance in 5 sec = 25m

Total distance = 650 m

Displacement = -600m

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