Question

A particle starts with a velocity of 10m/s and moves with a uniform acceleration of 2 m/s^2 ,find its velocity after 4 seconds.​

Answer 1

Explanation:

the answer is 18 m/s

v=u+at

v=10+2×0

v=0

again

v=10+2×4

v=18m/s

Answer 2

Answer:

• Velocity after 4 second is 18 m/s.

Explanation:

Given:

• Initial velocity (u) = 10 m/s
• Acceleration (a) = 2 m/s²
• Time (t) = 4 sec.

To Find:

• Final velocity (f).

Now, from 1st equation of motion.

=> v = u + at

Put the values.,

=> v = 10 + 4 × 2

=> v = 10 + 8

=> v = 18 m/s

Hence, velocity after 4 second is 18 m/s.

Extra Information:

>> Equation of motion:

1. v = u + at
2. s = ut + 1/2 at²
3. v² = u² + 2as.