Question

A particle starts with a velocity of 5m/s and moves with a uniform acceleration of 2.5m/s².distance travelled in 4s is ​

Answer 1

Answer:

Given : u=5 m/s a=−2.5 m/s

2

t=4 s

Displacement S=ut+

2

1

at

2

∴ S=5×4+

2

1

(−2.5)(4)

2

=0 m

Explanation:

hope you are satisfied with the answer

Answer 2

Physics

velocity : 5 m/s

acceleration : 2,5 m/s²

time = 4 seconds

distance : ____?

Answer :

D = V × t + 1/2 × a × t²

D = 5 × 4 + 1/2 × 2,5 × 4²

D = 20 + 1/2 × 2,5 × 16

D = 20 + 2,5 × 8

D = 20 + 20

D = 40 meters