Question

A particle starts with an initial velocity 3 m/s along the positive X-axis and it accelerates uniformly at the rate of 0.60 m/s2.how much it cover in reaching the velocity 9m/s.

Answer 1

Answer:

The given motion is under constant acceleration.

Using the motion equation

V^2 - U^2 = 2aS

S = (V^2 - U^2)/2a

= (81-9)/(2*0.6) = 72/1.2 = 60m

S = 60m

Answer 2

Explanation:

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