Question

A particle starts with certain initial velocity and
uniform acceleration, covers a distance of 12 m in
first 3 seconds and a distance of 30 m in next
3 seconds. The acceleration of particle is​

Answer 1

the acceleration of the particle will be 6m/s sq

Answer 2

Explanation:

By equ of motion

s=ut+1/2*at^2

12=3u+9/2a. ( distance for first 3sec )

42=3u+18a. (distance covered in 6sec)

two algebra equ on solving

we get 9a=18

so a = 2m/sec