a particle starts with moving acceleration 2 m/s^2. distance travelled by it in 5th half second is
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Here,
a=2m/s^2,u=0m/S,t=2and a half second
As we know,
S=ut+1/2at^2
=>S=0×2½+(1/2)×2×(2½)^2=0+6¼=6¼m
a=2m/s^2,u=0m/S,t=2and a half second
As we know,
S=ut+1/2at^2
=>S=0×2½+(1/2)×2×(2½)^2=0+6¼=6¼m
Jamesnain44:
sorry it's wrong answer
no problem give the right one so that i can learn from my mistake
the u is 0 so the formula which will be used is 1/2at^2 and then you will subtract the value of 2 seconds from answer then it will be 2.25. because it has been asked about 2.5th second not of 2.5
I didn't understand
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