Question

a particle starts with the velocity of 7m/sec and moves with acceleration of 4.9m/sec^2.its velocity after 4 sec is​

Answer 1

Answer:

Velocity of particle after 4 second is. 26.6m/s.

Explanation:

According to the Question

It is given that ,

• Initial velocity ,u = 7m/s
• Acceleration ,a = 4.9m/s²
• Time ,t = 4s

we need to calculate the velocity of particle after 4 second.

So we 'll applied here the kinematics equation

• v = u + at

where,

v denote Final Velocity

u denote initial velocity

a denote acceleration

t denote time taken

Substitute the value we get

➻ v = 7 + 4.9×4

➻ v = 7 + 19.6

➻ v = 26.6m/s

• Hence, the velocity of particle after 4 second is 26.6m/s.

Answer 2

• initial velocity=u=7m/s
• Acceleration=a=4.9m/s^2
• Time =t=4s
• Final velocity=v=?

According to first equation of kinematics

$\boxed{\sf v=u+at}$

$\\ \sf\longmapsto v=7+(4.9)(4)$

$\\ \sf\longmapsto v=7+19.6$

$\\ \sf\longmapsto v=26.6m/s$

Velocity of particle after 4s is 26.6m/s.