Question

A particle starts with velocity 10 ms-1 and
deacceleration of 5 ms-2. Find displacement and
distance traversed in 3 sec.?
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Answer 1

Answer:

Step-by-step explanation:

displacement=10 ms -1 -5 ms-2=5 ms-2 this can also be written as 5m/s^2

velocity = 10m/s^1 so particle cover distance = 10*3 =30

therefor a particle cover 30 meter

Answer 2

Answer:

30m

Step-by-step explanation:

v=u+at

v=10+(-5)6

v=10-30

v=-20m/s

v^2=u^2+2aS

20*20=10*10+2(-5)S

400=100-10S

300=-10S

S=-30m