Question

A particle starts with velocity 10ms¯¹ the acceleration of particle is 2ms¯² then the velocity of particle at time=4sec is.?

145mkn554#56
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Answer 1

Given:

• Initial velocity = 10m/s
• Acceleration = 2m/${s}^{2}$
• Time = t = 4sec

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Need to find:

• Final velocity = v =?

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Solution:

We know from the first equation of motion, that:

v = u + at

→ v = 10 + 2 × 4 m/s

→v = 10 + 8 m/s

→ v = 18m/s

The velocity of the particle at t= 4sec is 18m/s.

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Displacement in that time:

${v}^{2} - {u}^{2} = 2as$

→${18}^{2} - {10}^{2} = 2 \times 2 \times s$

→ 324 - 100 = 4s

→ 4s = 224 m

→ s = 224 ÷ 4m

→ s = 56m

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Knowledge cell:

• 1st equation of motion: v = u + at

• 2nd equation of motion: $s = ut + \dfrac{1}{2} a {t}^{2}$

• 3rd equation of motion:${v}^{2} - {u}^{2} = 2as$

• Velocity = Displcement ÷ Time

• s = $\dfrac{u + v}{2} t$

• Snth= u+ $\dfrac{a}{2} (2n- 1)$

• The equations of motions are used to derieve final velocity, initial velocity acceleration, displacement or time taken.

Answer 2

Answer:

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