A particle starts with velocity 10ms¯¹ the acceleration of particle is 2ms¯² then the velocity of particle at time=4sec is.?
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Answered by
1
v=u+at
= 10+2×4
=10+8
=18 m/s
= 10+2×4
=10+8
=18 m/s
Answered by
2
HEYA!!
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Given that ,
Initial Velocity = 10 ms-1
Acceleration = 2ms-2
Time = 4sec.
Using
V = U + AT [ First equation of motion ]
V = 10 + 2 ( 4 )
V = 10 + 8
V = 18 m/s
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--_-----_--
Given that ,
Initial Velocity = 10 ms-1
Acceleration = 2ms-2
Time = 4sec.
Using
V = U + AT [ First equation of motion ]
V = 10 + 2 ( 4 )
V = 10 + 8
V = 18 m/s
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