Question

A particle strikes a horizontal frictionless floor with a speed u at an angle theta with the vertical . The coefficient of restitution is e then magnitude of v is

Answer 1

Answer:

u √(Sin 2θ + e2 cos 2θ)

Explanation:

In the horizontal direction, momentum must be conserved, as the floor is friction less and there is no horizontal force. musin θ = mvsin θ. In the vertical direction, vcos ϕ = eucos θ

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