A particle strikes a stationary object with the speed u. Speed of the 2nd object after the collision will be???
Answers
mv1 - mu1
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an elastic collision, e=
RVOA
RVOS
=−
u
1
−u
2
v
1
−v
2
=1
Let
u
1
an elastic collision, e=
RVOA
RVOS
=−
u
1
−u
2
v
1
−v
2
=1
Let
u
1
be the velocity of A before collision,
u
2
be the velocity of B before collision=0
v
1
be the speed of A after collision
v
2
be the speed of B after collision
From conservation of momentum,
m
1
u
1
+m
2
u
2
=m
1
v
1
+m
2
v
2
m
1
u
1
=m
1
v
1
−m
2
v
1
.................................(1)
e=−
u
1
−u
2
v
1
−v
2
=1
v
2
−(−v
1
)=u
1
−u
2
2v
1
=u
1
..............................................(2)
Putting (2) in (1)
2m
1
v
1
=m
2
v
1
−m
1
v
1
⇒3m
1
v
1
=m
2
v
1
⇒
m
2
m
1
=
3
1
be the velocity of A before collision,
u
2
be the velocity of B before collision=0
v
1
be the speed of A after collision
v
2
be the speed of B after collision
From conservation of momentum,
m
1
u
1
+m
2
u
2
=m
1
v
1
+m
2
v
2
m
1
u
1
=m
1
v
1
−m
2
v
1
.................................(1)
e=−
u
1
−u
2
v
1
−v
2
=1
v
2
−(−v
1
)=u
1
−u
2
2v
1
=u
1
..............................................(2)
Putting (2) in (1)
2m
1
v
1
=m
2
v
1
−m
1
v
1
⇒3m
1
v
1m