Question

A particle strikes elastically with another particle with velocity V after collision its move with half the velocity in the same direction find the velocity of the second particle if it is initially at rest-
1)3V/2
2)V/2
3)V
4)0

Answer 1

Answer:3v/2

Explanation:Aacording to newton's law of restitution (velocity of sepration)=e*(velocity of approch )

So, e for elastic body is 1 and then, u1-u2=v2-v1

U2 is given zero and u1 is v , v1 is given v/2 so relation becomes v=v2-v/2 , by solvibg u get v2=3v/2 , thanks

Answer 2

Answer:

Answer:3v/2

Explanation:Aacording to newton's law of restitution (velocity of sepration)=e*(velocity of approch )

So, e for elastic body is 1 and then, u1-u2=v2-v1

U2 is given zero and u1 is v , v1 is given v/2 so relation becomes v=v2-v/2 , by solvibg u get v2=3v/2 , thanks

Explanation: