Question

A particle travel 10m during the 4th and 9.2m during the 6th second. Find the initial velocity and acceleration.​

Answer 1

Explanation:

Let assume initial velocity is u and constant acceleration a. using s=ut + (0.5)at

2

,

for first 5 second

10 = 5u + (0.5)a(25)

for next 3 seconds, t=8 and s=20

20=8u+(0.5)a(64)

Solving,

a=

3

1

and u=

6

7

Now for next 2 seconds, t=10 and S

′

:

S

′

=(10)

6

7

+(0.5)

3

1

(100)

S

′

=

6

170

Now distance travelled in 2 sec =

6

170

−20=

6

50

meter