Question

A particle travel 1st half distance with uniform speed of 40m/s and next half distance with uniform speed of 80m/s calculate average speed

Answer 1

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Answer 2

Given:

A particle travel 1st half distance with uniform speed of 40m/s and next half distance with uniform speed of 80m/s.

To find:

Average speed.

Calculation:

Average speed is defined as the total distance divided by the total time taken to cover that specific distance.

Let each half distance be "s".

$\rm \therefore \: avg. \: v = \dfrac{total \: distance}{total \: time}$

$\rm = > \: avg. \: v = \dfrac{s + s}{( \frac{s}{40} ) + ( \frac{s}{80} )}$

$\rm = > \: avg. \: v = \dfrac{2s}{( \frac{s}{40} ) + ( \frac{s}{80} )}$

$\rm = > \: avg. \: v = \dfrac{2}{( \frac{1}{40} ) + ( \frac{1}{80} )}$

$\rm = > \: avg. \: v = \dfrac{2}{( \frac{2 + 1}{80} ) }$

$\rm = > \: avg. \: v = \dfrac{2}{( \frac{3}{80} )}$

$\rm = > \: avg. \: v = \dfrac{2 \times 80}{3}$

$\rm = > \: avg. \: v = \dfrac{160}{3}$

$\rm = > \: avg. \: v = 53.3 \: m {s}^{ - 1}$

So, average speed of the object is 53.3 m/s.