Question

A particle travel 1st half distance with uniform speed of 40m/s and next half distance with uniform speed of 80m/s calculate average speed solve in physics​

Answer 1

Answer:

53.33 m/s

Explanation:

Let the distance be 2x.

He travels x distance with speed 40 m/s

Therefore the time taken is x/40

He travels the remaining x distance with speed 80 m/s

Therefore the time taken is x/80

Therefore the average speed is $\frac{total distance}{total time}$

Total distance = 2x

Total time =

$\frac{x}{40} + \frac{x}{80}\\\\=\frac{2x+x}{80}\\\\\\= \frac{3x}{80}$

average speed =

$\frac{2x}{\frac{3x}{80} }\\ \\\frac{2}{3} X 80\\ \\\\\frac{160}{3}\\ \\= 53.33 m/s$

Ans 53.33 m/s

Answer 2

Answer:

Average speed = 53.33 m/s

Explanation:

Given:

• The particle travels half of the distance with a speed of 40 m/s
• The particle travels other half of the distance with a speed of 80 m/s

To Find:

• Average speed of the particle

Solution:

Let us assume the total distance travelled by the particle as 2 x

We know that

Time = Distance/Speed

In the first case:

Distance = x

Speed = 40 m/s

Hence,

Time = x/40 s

In the second case:

Distance = x

Speed = 80 m/s

Time = x/80 s

Now we know that,

Average speed = Total distance travelled/Total time taken

Substituting the data,

Average speed = x + x/(x/80 + x/40)

Average speed = 2x/(40x + 80x)/3200

Average speed = 2x/120x/3200

Cancelling x on both numerator and denominator,

Average speed = 2 × 3200/120

Average speed = 6400/120

Average speed = 53.33 m/s

Hence average speed of the particle is 53.33 m/s

Notes:

The average speed of a body is the total distance travelled by it divided by the total time taken to cover the distance.

Average speed = Total distance travelled/Total time taken