Question

a particle travel a distance of 20m in the 7th s and 24 m in 9th s . how much distance shall in travel in the 15th s ? please ansewr fast.​

Answer 1

Explanation:

distance in 7 sec=20m

distance in 9 sec=24m

distance in one sec=4/2=2m

distance in 15 sec=6×2=12

The distance travel in 15th s=36m

Answer 2

This can be also be saved logically as

7sec= 20

9 sec =24

11sec =28

13sec 32

15sec 36

but in some cases/problems it is not possible as values may be critical so I have solved it in proper steps in the attachment

Note this formula as it is useful in suchproblems

$distance \: in \: nth \: sec = u + \frac{1}{2} a(2n - 1)$

hope it helps...

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