A PARTICLE TRAVEL FROM A:B:C:D=2:1:5 AND DURING AB,BC AND CD IT'S SPEED ARE 4m/s,2m/s and 10m/s respectively.find average speed
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Answer:As shown in the figure, total distance will be of length 3 sides but total displacement will be just side AD.
Total time = 25+25+25 /15
=5s
Total displacement =25 m
Average velocity = 25/5
=5m/s
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Answer:
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