Question

A PARTICLE TRAVEL FROM A-B-C-D AND AN:BC:CD=2:1:5 and during AB,BC AND CD . ITS SPEED ARE 4M/S ,2M/S AND 10M/S RESPECTIVELY FIND AVERAGE SPEED:-


(need correct answer please please)

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Answer 1

Answer:

As shown in the figure, total distance will be of length 3 sides but total displacement will be just side AD.

Total time =

15

25+25+25

=5s

Total displacement =25 m

Average velocity =

5

25

=5m/s

Explanation:

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Answer 2

Answer:

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Explanation:

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