A particle travel half distance with uniform speed 40m/s and next half distance with uniform speed 80m/s calculate average speed.
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Solution:-
Part I :-
- Speed ( s)= 40 m/s
Let the total distance traveled by the particle be d
- Distance(d') = d / 2
we know that ,
⟹ s = d' / t '
On rearranging ,
⟹ t ' = d ' / s
⟹ t ' = d / 2 x 40
⟹ t ' = d / 80
Part II :-
- Speed ( s")= 40 m/s
Let the total distance traveled by the particle be d
- Distance(d") = d / 2
we know that ,
⟹ s = d" / t "
On rearranging ,
⟹ t " = d " / s
⟹ t " = d / 2 x 80
⟹ t " = d / 160
Part III :-
⟹ Average speed = total distance / total time
⟹ Average speed = d / t' + t"
⟹ Average speed = d / d / 80 + d / 160
⟹ Average speed = d / 2d+d / 160
⟹ Average speed = d x160 / 3d
∴Average speed = 53.33 m /s
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