Question

A particle travel in a circular path of radius 0.2 with
the constant kinetic energy of 4 schedule what is the net force on this particle​

Answer 1

Answer:

The Ans is 40n

Explanation:

The important thing we don't know for this question is mass, so we need to find a formula for the mass of the particle.

Since we know the kinetic energy, we know that

Ek = 0.5mv2

4 = 0.5mv2

So m = 8/v2

The force acting on the particle will be centripetal force (keeping it in a path of circular motion), which has the equation

F = mv2 /r

Substituting out previous formula for m into this, we get

F = 8/V2 * V2 / r

The V2 s cancel out, and r=0.2m so we get

F = 8/0.2

So the net force is 40N.

Answer 2

Answer:

the centripetal force=K.E

mv^2/r =1/2mv^2

put the value and u will get your ans.

using force formula