Question

A particle travel with initial velocity of plus 6.0 metre per second and moves with an acceleration of -2.0 metre per second square calculate the displacement of the particle after 5seconds

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Answer 1

Answer:

Explanation:u = 6m

a= -2m²

t= 5sec

a=v-u/t

-2=v-6/5

V=-4

D=s/t

S=?

v²-u²=2as

-4²-6²=2*-2*s

S=5

D=s/t

D=5/5

D=1

Answer 2

Initial Velocity = 6m/s

Acceleration = -2m/s

Time = 5 s

We know, s = ut + 1/2 at²

Substituting in the formula

6×5 + 1/2× (-2)×5²

30+(-50)/2

30-25

=5 m is the displacement after 5 secs