Question

a particle travels 10 m in first 5 secs, 10 m in next 3 secs. assuming constant acceleration, what is the distance travelled in next 2 sec? Answer =83m

Answer 1

let the acceleration be a.
given:
s=ut+1/2at²
10=5u+1/2×25×a
10=(10u+25a)/2
20=10u+25a
also
distance=10+10=20 in time5+3=8
20=8u+1/2a64
20=(16u+64a)/2
40=16u+64a
on solving we get a=1/3 and u=7/6
so the distance travelled in next 2s=total distance-distance travelled in 8s
7/6×10+1/2×1/3×10×10-20
170-120/6
50/6

Answer 2

Answer:

Step-by-step explanation:

see the next answer

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