a particle travels 10 m in next 3 seconds . assuming constant acceleration what is distance travelled by it in next 2 second .
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Let assume initial velocity is u and constant acceleration a.
using s=ut+.5 a t^2
For first 5 second
10=5 u +.5x a x 25..........(1)
for next 3 seconds t=8 and s=20
20=8 u+.5xax64...........(2)
Solving 1 and 2
a=1/3 and u=7/6
Now for next 2 seconds t=10 and s'
S'=10x7/6 +.5x(1/3) 100
S'=170/6
Now distance travelled in 2 sec=(170/6)-20=50/6 meter
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