a particle travels 100 m after starting from rest in 10 s its acceleration is
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Answered by
18
Hey dear here is your answer.....
Let u =0m/sec
Let the=10 sec
S=ut+1/2at^2
100=0+1/2a100
200=100a
a=2m/sec^2
hope it may helps u ...
Let u =0m/sec
Let the=10 sec
S=ut+1/2at^2
100=0+1/2a100
200=100a
a=2m/sec^2
hope it may helps u ...
sridharganesh1pb29mf:
thank you friend
Answered by
5
Let, s=distance covered by the particle.
u=primary velocity of particle.
f=acceleration of particle.
t=time
Then, we have
s=ut + (1÷2)×f×(t^2)
here s=100m t=10 sec u=0
so, 100= 0+ (1÷2)×f×100
or, f=2 m/(sec^2)
u=primary velocity of particle.
f=acceleration of particle.
t=time
Then, we have
s=ut + (1÷2)×f×(t^2)
here s=100m t=10 sec u=0
so, 100= 0+ (1÷2)×f×100
or, f=2 m/(sec^2)
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