Question

A particle travels first half of the total time with constant speed v1 and the second half with v2. Find the average speed.​

Answer 1

Answer:

Average Vel. = (v1 + v2) /2

Explanation:

Let the total time is = t

For first half time the velocity is v1 and time is t/2

Since displacement = Vel. * time

so displacement in first half ( S1 ) = v1 * t/2

For second half time the velocity is v2 and time is t/2

Since displacement = Vel. * time

so displacement in second half ( S2 ) = v2 * t/2

Now average velocity = Total displacement/ total time

total displacement= S1+ S2

= v1 * t/2+v2 * t/2

and total time = t

So AVE velocity = (v1) t + ( v2) t / 2t

On taking t common and cancelling we get

Average Vel. = (v1 + v2) /2

Answer 2

Answer:

v1+be/2

Explanation:

Avg speed=total distance/total time taken

Si, the required avg speed=v1+v2/2