A particle travels for 40 seconds under the influence of a constant force.if the distance travelled by the particle is S1 in the first twenty seconds and S2 in the next twenty seconds,then
Options
A-S2=S1
B-S2=2S1
C-S2=3S1
D-S2=4S1
Plz solve it to be the brainliest
Answers
Answered by
64
C- S2 = 3 S1
s = ut + 1/2 at^2
S1 = 0 + 1/2 a(20)^2
S1 = 200 a
v = u + at
v = 0 + a*20
v = 20a
S2 = 20a*20 + 1/2 * a * 20^2
S2 = 600a
S1/S2 = 200a / 600a = 1/3
S2 = 3S1
s = ut + 1/2 at^2
S1 = 0 + 1/2 a(20)^2
S1 = 200 a
v = u + at
v = 0 + a*20
v = 20a
S2 = 20a*20 + 1/2 * a * 20^2
S2 = 600a
S1/S2 = 200a / 600a = 1/3
S2 = 3S1
sachin526:
yep
Answered by
5
Explanation:
Above answer is correct.
Similar questions