Question

a particle travels from point a to b on a circular path of radius 15/p cm. if the arc length ab be 10cm, find the displacement

Answer 1

the angle covered by man is 10/15 rad
1 rad=180/pi degrees
10/15 rad=(180/pi)*(10/15) degrees=38.197 degrees
Now displacement is given by cosine law
let l be displacement
$l^2=2r^2-2r^2cos(38.197)=2(100)(1-cos(38.197))=42.823$
$l=6.5434 cm$
is the displacement

Answer 2

Angle Covered man = 10/15
rad 1 rad = 180/pi degrees
10/15 rad =(180/pi)*(10/15) degrees=38.197 degrees
Now displacement is given by cosine law
let l be displacement l^2=2r^2-2r^2cos
(38.197)=2(100)(1-cos(38.197))=42.823

displacement = l=6.5434 cm