A particle travels half of the distance of a straight journey with a speed 6 m/s. The remaining part of the distance is covered with speed 2 m/s for half of the time of remaining journey and with speed 4 m/s for the other half of time. Find the average speed of the particle.
Answers
Answered by
1
Answer:
4.5m/s
Explanation:
We can take any number so
We are taking 100
so , 50 by 6m/s , 25 by 2m/s ,25 by 4m/s
50*6+25*2+25*4
300+50+100
450
then, 450/100
4.5
then , average speed will be 4.5m/s
Answered by
1
Answer:
Correct option is
B
4m/s
Let the total distance be d.
In the first part of journey, particle travels distance 2d with speed 6m/s, so corresponding time.
t1=62d=12ds
The times of second and third parts of the journey are equal t2=t3. The sum of distances of these
parts are 2d Let the distance of the second part of the journey be x. Then
t2=t3→2x=42d−x→x=6dm,
t2=26d=12d=t3
Total time of journey:
T=t1+t2+t3=312
Explanation:
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