A particle travels in a circular path of radius 0.2m with constant kinetic energy of 4 J. what is the net force on this particle?
Answers
Answered by
1
Explanation:
ke = force *radius
4= force * radius
4/0.2=force
force =20N
Answered by
11
Answer:
F = 40 N
Explanation:
Fc = mv²/r=2(1/2mv²)/r
=2K.E/r = 2(4)/0.2=40 N
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