Question

A particle travels with uniform velocity of 5m/s, due north for 3 seconds. It stops in negligible time and then travels with uniform velocity of 10 m/s, due south, for 7 seconds. The average velocity of the particle is (only magnitude)​

Answer 1

Explanation:

CASE 1:

A PARTICLE TRAVELS WITH UNIFORM VELOCITY OF ,5M/S

DUE TO NORTH FOR 3 SECONDS.

V=5 M/S

T=3 SECONDS

DISPLACEMENT =V×T=5×3=15 M

CASE 2:

A PARTICLE STOPS AND THEN MOVE WITH UNIFORM VELOCITY OF 10 M/S,DUE SOUTH FOR 7 SECONDS.

V=10 M/S

T=7 SECONDS

DISPLACEMENT =V×T=10×7=70 M

NOW AVERAGE VELOCITY =TOTAL DISPLACEMENT/TOTAL TIME TAKEN.

=15+70/3+7

=85/10

=8.5 M/S