Question

A particle traversed half of the distance with a velocity V0. The remaining parts of the distance was covered with velocity V1, for half of the time. Find the mean velocity of the particle averaged and the whole time of motion. (its Urgent plz)(and plz *elaborate* *step by step* plz)

Answer 1

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Answer: 2v0(v1+v2)2v0+v1+v2

Average velocity v¯¯¯=2v1v2v1+v2

In this case, a body travels first half a distance with velocity v0→v1=v0.

For the 2nd half, average velocity v2=12(v1+v2)

⇒v¯¯¯=2v0v1+v22v0+v1+v22

⇒v¯¯¯=2v0(v1+v2)2v0+v1+v2

Answer 2

Direct formula that is derived is

Velocity =2(V0*V1) ➗ V0+V1

Hope it's helpful

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