Question

A particle traverses a semi-circular path of
1m radius in 1s time. What is the average
velocity of the particle?
@ 3.14 m/
s
® 2 m/s
© 1 m/s
O zero​

Answer 1

$\Large\underline{\underline{\sf Given:}}$

• Semi-circular path of radius (r) = 1m

• Time (t) = 1s

$\Large\underline{\underline{\sf To\:Find:}}$

• Average Velocity of Particle (v).

$\Large\underline{\underline{\sf Formula\:Used:}}$

${\boxed{\boxed{\sf \pink{Average\: Velocity=\dfrac{Displacement}{Time}}}}}$

$\Large\underline{\underline{\sf Solution:}}$

Displacement : defined as change in position of an object , it is measured from initial point to final point.

⛬ Displacement of semi-circle of radius r is 2r.

$\implies{\sf V=\dfrac{2r}{t}}$

$\implies{\sf V=\dfrac{2×1}{1} }$

$\implies{\sf V=2\:m/s }$

$\Large\underline{\underline{\sf Answer:}}$

Option (b) 2m/s

Average Velocity of Particle is 2m/s

Answer 2

Answer:

$\large\bold\red{2\:m{s}^{-1}}$

Step-by-step explanation:

Given,

A particle trasverses a semi Circular path,

• Radius, r = 1 m

Now,

We have to find the average velocity.

But,

We know that,

$\large\boxed{\bold\purple{Average\: Velocity,v=\frac{Displacement}{Time}}}$

But,

We know that,

Displacement in semicircle = 2r = 2 m

Also,

It's given that,

Time = 1 s

Therefore,

$= > v = \frac{2}{1} \\ \\ = > \bold{ v = 2 \: m {s}^{ - 1}}$