A particle undergoes SHM having time period T. Find the time taken in (3/8)th 9 oscillation.
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Answered by
116
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Your answer:-
Time taken to complete one fourth oscillation T/ 4
so time to complete 1/8th oscillation from to extreme position is obtained from
y= a/2 = a cos cot = a cos 2 pai / T × t
0r cos Pai /3 = cos 2pai t/ T
t = (T/6) s
hence time to complete 3/8th oscillation
= T/4 + T/6
= 5T /12
___________
___________
I Hope it's help you.... :))
__________
__________
Your answer:-
Time taken to complete one fourth oscillation T/ 4
so time to complete 1/8th oscillation from to extreme position is obtained from
y= a/2 = a cos cot = a cos 2 pai / T × t
0r cos Pai /3 = cos 2pai t/ T
t = (T/6) s
hence time to complete 3/8th oscillation
= T/4 + T/6
= 5T /12
___________
___________
I Hope it's help you.... :))
Answered by
14
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