A particle v =3t^2 on straight track. Find average velocity in first 10 seconds
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v = 3t^2
displacement (t) = integration of the relationship.
= t^3
d (10secs) = 1000 units
avg. velocity = 1000/10= 100.
displacement (t) = integration of the relationship.
= t^3
d (10secs) = 1000 units
avg. velocity = 1000/10= 100.
utk494966p6o41q:
11
then this is the correct method
are u having any difficulty..let me know.
i know but i m new in 11
have u studied integration?
do u know easy method ?
nope..this is the only method..
ok
u can find velocity at each second.
and then find their mean
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