A particle was at rest from 1am. It moved at uniform speed50km/hour from 1:30am to 2:00am.find the average speed between a)1:00am to2:00am b)1:15am to 2:00am c)1:30am to 2:00am.
Answers
time when the particle was at the rest = 1 AM
uniform speed of 50 km/h = 1:30 am to 2:00 am
a)distance covered between 1:30 & 2:00 am= speed * time= 50 *1/2=25km
average speed = total distance/total time taken
= 25/1 = 25km/h
b)average speed = 25/(3/4) =33km/h
c)average speed=25/(1/2)=50km/h
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Concept:
The average speed can be defined as the total distance with respect to the total time taken.
a = u/t
where a is average speed, u is the total distance traveled and t is the total time taken,
Given:
The uniform speed, u = 50km/hour.
Find:
The average speed between (a) 1:00am to 2:00am (b) 1:15am to 2:00am and (c) 1:30am to 2:00am.
Solution:
Total distance covered between 1:30 & 2:00 am
d = speed × time = 50 × 30/60
d = 50/2 = 25 km
(a) The total time taken from 1:00 am to 2:00 am is 1hr,
a = u/t
a = 25km/1 hr = 25 km/hr
The average speed between 1:00 am to 2:00 am is 25 km/hr.
(b) The total time taken from 1:15 am to 2:00 am is 3/4hr,
a = u/t
a = 25km/(3/4) hr
a = 100/3 km/hr
The average speed between 1:15 am to 2:00 am is 100/3 km/hr.
(c) The total time taken from 1:30 am to 2:00 am is 1/2 hr,
a = u/t
a = 25km/(1/2) hr
a = 50 km/hr
The average speed between 1:30 am to 2:00 am is 50 km/hr.
Hence, the average speed between 1:00 am to 2:00 am, 1:15 am to 2:00 am and 1:30 am to 2:00 am is 25 km/hr, 100/3 km/hr, and 50 km/hr respectively.
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