Question

a particle was at rest from 9:00 am to 9:30 am it moved ata uniform speed at 10km/ hr from 9:39 am to 10:00am find avrage speed between a 9: am to 10: am​

Answer 1

Answer:

Given conditions ⇒

Speed of the Particles = 10 km/hr.  

As per as the Question, we need to find the Average speed of the Particles between 9 am to 10 am.  

∴ Total time = 1 hrs.  

Speed of the Particles between 9 to 9:30 am = 0  

∴ Distance covered by the Particles in 30 minutes = 10 × 0.5

= 5 km.  

Average speed = Total Distance/Total time.  

∴  = 5 × 1  

   = 5 km/hr.  

Hence, the average speed of the Particles is 5 km/hr.  

___________________________

(b). Distance covered in 30 minutes = 5 km.  

Total time taken by it = 45 minutes.  

= 45/60 hrs.  

= 3/4 hrs.  

∴ Average Speed = 5/(3/4)

   = 20/3  

   = 6.67 km/hr.  

Hence, the average speed of the Particles is 6.67 km/hr.  

Hope it helps. :-)

Explanation:

Answer 2

Given

speed of particle -10km/hr

9:30 to 10:00

distance= speed ❌ time

= 10 ✖️ 0.5

= 5km/hr

Explanation:

distance covered in 30 min = 5km

Total time taken = 45min ( bcz it started from 9: 15)

change 45 min into hour ( 45/60)= 3/4 hrs

avg speed = total distance/total time

= 5÷ 3/4

= 5 ❌ 4/3

= 20/3

= 6.67km/hr ans

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