Question

a particle was at rest from 9 am it moved at a uniform speed of 10 km/hr from 9:30 am to 10 am find the average speed between 9:15 am to 10 am

Answer 1

Distance travelled between 9:30 to 10:00 i.e in 30 min or in 0.5 hr = speed×time
distance = 10×0.5 = 5 m

Avg speed between 9:00 to 10:00 i.e. in 1 hr
= total distance travelled / total time taken
= 5/1
= 5 km/hr


Time between 9:15 to 10:00 = 45 min = 3/4 hr
avg speed = 534 = 203 = 6.66 km/hr
PLZ MARK AS BRAINLIEST ANSWER.