A particle weighing 8 kg is allowed to fall under the force of gravity. what is its momentum at 2 seconds?
Answers
Answered by
0
Velocity after 2s
v = u + at
v = 0 + (9.8×2)
v = 19.6 m/s
Momentum = mv
= 8kg × 19.6m/s
= 156.8 kgm/s
Note: Momentum = 160 kgm/s [If g = 10m/s²]
v = u + at
v = 0 + (9.8×2)
v = 19.6 m/s
Momentum = mv
= 8kg × 19.6m/s
= 156.8 kgm/s
Note: Momentum = 160 kgm/s [If g = 10m/s²]
Answered by
3
momentum is mass×velocity
therefore,
we need to find its velocity after 2 second applying first equation of motion,
v=u+at,. v=0+10×2 ==(20)
now momentum = mass×velocity =8×20
.....160kgm/s
therefore,
we need to find its velocity after 2 second applying first equation of motion,
v=u+at,. v=0+10×2 ==(20)
now momentum = mass×velocity =8×20
.....160kgm/s
Similar questions