A particle weighs 120 n on the surface of the earth.at what height above the earth's surface will its weigh be 30 n?
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mass of the partilce remains same i.e. m
only the aceleration due to gravitation varies because of increase in distance
let the height be h
thus on surface of earth
F = 120N =
R2 @-----eq1
(R is the radius of earth)
then at height h,
F' = 30N =
(R+h)2 @-----eq 2
dividing these two equations we get
4 = (R+h)2 / R2
or 2 = (R+h)/R
or h = R
mass of the partilce remains same i.e. m
only the aceleration due to gravitation varies because of increase in distance
let the height be h
thus on surface of earth
F = 120N =
R2 @-----eq1
(R is the radius of earth)
then at height h,
F' = 30N =
(R+h)2 @-----eq 2
dividing these two equations we get
4 = (R+h)2 / R2
or 2 = (R+h)/R
or h = R
Answered by
3
Hlo Every one this is the answer hope it will help you
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