Question

A particle weighs 120 N on the surface of the earth. At what height above the earth's surface will its weigh be 30 N? (Take, radius of the earth=6400 km)

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Answer 1

Answer:

we know

g = GM/r² ----- (1)

If the body taken to the height above earth surface

g = GM/( r + h)² ----(2)

Dividing (2) by (1)

we get ,

1/4 = r²/(r+h)²

Taking square roots on both sides

1/2= r/(r+h)

r + h = 2 r

h = r

h = 6400 k m

Explanation:

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