Question

A particle weight 120 newton on the surface of the earth. At what height above the earth surface will its weight be 30newtons??​

Answer 1

Answer:

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Answer 2

answer

6400 km

Explanation:

Let's see ,

We know that F= GMm/r² is the equation for gravity.

Where F is the force ( or weight) M is the mass of first object, and m is of second, and r is the distance between the centres of the objects.

Now in the first case scenario when the object is at the surface of the earth,

120N = GMm/6400²

Which means,

GMm= 120× 6400² or GMm= 120×6400×6400 ___(I)

So now in the second case scenario,

30N= GMm/r²

Where r is the unknown height,

Now from _(I)

30N= 120×6400×6400/r²

Or..

r²= 120×6400×6400/30

r²= 4× 6400 ×6400

r²= 163840000km

r= √163840000

r= 12800km

But remember it is the distance of the object from the centre of the earth, so from the surface of the earth it would be..

12800–6400= 6400km