Question

A particle which is projected at such an angle with the horizontal range is six times the greatest height attained by the particle. Find the angle of projection​

Answer 1

Answer:

horizontal range = u²sin2\phi /g

maximum height =u²sin²ϕ/2g

A/C to question,

horizontal range =3× maximum height

u²sin2ϕ/g=3×u²sin²ϕ/2g

$${ sin2\phi = 2sin\phi .cos\phi }$$

2sinϕ.cosϕ=3/2.sin²ϕ

tanϕ=4/3

ϕ=tan⁻¹(4/3)

Hence,

Explanation:

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Answer 2

Explanation:

A particle which is projected at such an angle with the horizontal range is six times the greatest height attained by the particle. Find the angle of projection is x is answer