A particle whose speed is 5V6 m/s moves along the line from A (1, 0, 3) to B (3, 2, -1). Find its
velocity vector in the form of ai + bj + ck
1(A5 +59 - 10K (B) 5* + 109 – 10K (C) 5* +5j + 10K (D) None of these
Attachments:
Answers
Answered by
2
mutiply both sides by zeros.
Answered by
2
Answer:
Explanation:
3 2 -1
+
1 0 3
Sol : 4i+2j-2k
None of these
Similar questions