Science, asked by IITB, 10 months ago


A particle whose speed is 5V6 m/s moves along the line from A (1, 0, 3) to B (3, 2, -1). Find its
velocity vector in the form of ai + bj + ck
1(A5 +59 - 10K (B) 5* + 109 – 10K (C) 5* +5j + 10K (D) None of these

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Answers

Answered by Rushabh15
2

mutiply both sides by zeros.

Answered by notrajdep1337
2

Answer:

Explanation:

3 2 -1

+

1 0 3

Sol : 4i+2j-2k

None of these

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