Question

A particle will leave a vertical circle of radius r, when its velocity at the lowest point of the circle(v1)

is

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Answer 1

Answer:

given = radius= r

         

to find  = velocity

solution =

                     1/2 mv²  = mgr

                     1/2 v² = 3/2 gr

                      v= $\sqrt{3gr}$

a particle will leave a vertical circle when velocity is v= $\sqrt{3gr}$.

Answer 2

Explanation:

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