Question

A particle with 10*-11 c of charge 10*-7 kg mass is moving with a velocity of 10*8 along y axis. A uniform static magnetic field 0.5 t is acting along x direction. Force is

Answer 1

magnetic force acting on particle is 5 × 10^-4 N along south direction.

charge on particle, q = 10-¹¹ C

mass of the particle, m = 10^-7 kg

velocity of particle, v = 10^8 j [as particle is moving along y-axis ]

magnetic field, B = 0.5 i T [ along x-axis ]

we know magnetic force, F = q(v × B)

= 10-¹¹( 10^8j × 0.5i)

= 10-³ × 0.5 (j × i)

= 5 × 10-⁴ (-k)

hence, magnetic force acting on particle is 5 × 10^-4 N along south direction.

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Answer 2

$\huge\bold\purple{Answer:-}$

charge on particle, q = 10-¹¹ C

mass of the particle, m = 10^-7 kg

velocity of particle, v = 10^8 j [as particle is moving along y-axis ]

magnetic field, B = 0.5 i T [ along x-axis ]

we know magnetic force, F = q(v × B)

= 10-¹¹( 10^8j × 0.5i)

= 10-³ × 0.5 (j × i)

= 5 × 10-⁴ (-k)

hence, magnetic force acting on particle is 5 × 10^-4 N along south direction.