Question

A particle with a charge of 1.5 coulombs is taken from a point A at a potential of 50V to another point B at a potential of 120V. Calculate the work done

Answer 1

Answer:

105 joule

Explanation:

Q=1.5 C

V1 = 50 V

V2 = 120 V

V = (120 - 50) V

= 70 V

V = W / Q

W = V Q

= 70 x 1.5

= 105 J