Question

A particle with a charge of 1.5 coulombs is taken from a point A at a potential of 50v to another point B at a potential of 120v . Calculate the work done

Answer 1

Given:- q = 1.5C

→V₁=50V

→V₂=120V

Work Done = ?

Solution: →V₂ - V₁ = W/q

→120-50 = W/1.5

→70 × 1.5 =W

→105=W

                                           Therefore, Work done = 105J

Answer 2

Answer:

A particle with a charge of 1.5 coulombs is taken from a point A at a potential of 50v to another point B at a potential of 120v . Calculate the work done