Question

A particle with a charge of 2.5 C is taken from a point A at a potential of 60V to another point B at a potential of 130V. Calculate the work done.​

Answer 1

Answer:

Explanation:

Explanation:As it is given:

Charge on particle = 2.5 C

Potential on A = 60 v

Potential on B = 130 v

So we know that ,

Potential difference = work done/charge

So, p.d = 130-60 = 70

Now, putting value of p.d and charge in above formula.

We get,

70 = work/2.5

Work = 70 × 2.5 = 175 joule